计算:(1)(-a)2-(a2)2÷(-a)3(2)(x-2)2-(x+3)(x-3)(3)20092-2010×2008(简便方法计算)
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答案如下:
(1)原式=a2?a4÷(-a3)
=-a3;
(2)原式=x2-4x+4-(x2-9)
=x2-4x+4-x2+9
=13-4x;
(3)原式=20092-(2009+1)
=20092-(20092-1)
=20092-20092+1
=1.
(1)原式=a2?a4÷(-a3)
=-a3;
(2)原式=x2-4x+4-(x2-9)
=x2-4x+4-x2+9
=13-4x;
(3)原式=20092-(2009+1)
=20092-(20092-1)
=20092-20092+1
=1.